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by Aamir Hasan   on Thursday, September 20, 2012
Here Aamir Hasan has explained how to drag and drop items from one list to another using jQuery UI plugin More
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by Aamir Hasan   on Friday, September 7, 2012
Here Aamir Hasan has explained how to disable right click on HTML div. More
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by Aamir Hasan   on Thursday, February 3, 2011
DetailsView Control displays each field of a single data as HTML table and ability to insert, update, and delete single record at a time... More
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by Aamir Hasan   on Tuesday, January 11, 2011
In this post, you will see how to get number of active visitor's online in asp.net web site... More
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by Aamir Hasan   on Friday, January 7, 2011
I was recently asked a question, that how to validate email address using jQuery in asp.net web site... More
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by Aamir Hasan   on Sunday, January 2, 2011
In this article you will see that how to load web user control dynamically using jQuery. More
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by Aamir Hasan   on Tuesday, December 21, 2010
The following example demonstrates how can we count number of column(s) in a table using jQuery More
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by Aamir Hasan   on Tuesday, December 21, 2010
The following example demonstrates how can we count the number of rows in a table using jQuery.. More
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by Aamir Hasan   on Monday, December 13, 2010
how to load web user control dynamically in your ASP.NET web form More
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by Aamir Hasan   on Monday, December 6, 2010
Yesterday developer asked me, distinct method on a column using linq is not woking. So, i have decided to wite this example in my blog to share with all of you. Let’s startOpen your Visual Studio 2008/2010 from File -> New -> New Web Site. Following is the code of Default.aspx page.<html xmlns="http://www.w3.org/1999/xhtml"><head runat="server">    <title></title></head><body>    <form id="form1" runat="server">    <div>        <asp:GridView ID="GridView1" runat="server">        </asp:GridView>    </div>    </form></body></html>Following is the code of Default.aspx.cs page. protected void Page_Load(object sender, EventArgs e)    {        GridView1.DataSource = from i in getAllEmployee()                               group i by i.FullName into temp1                               select temp1.Key;        GridView1.DataBind();    }    public List<Employee> getAllEmployee()    {        List<Employee> emp = new List<Employee>()        {            new Employee(){ ID=1, FullName="Aamir Hasan", Age=25 },            new Employee(){ ID=2, FullName="Awais Ahmed", Age=21 },            new Employee(){ ID=3, FullName="Saba khan", Age=11 },            new Employee(){ ID=4, FullName="Mahwish Hasan", Age=18 },            new Employee(){ ID=5, FullName="Hina", Age=26 },            new Employee(){ ID=6, FullName="John", Age=24 },            new Employee(){ ID=7, FullName="Aamir Hasan", Age=22 },            new Employee(){ ID=8, FullName="Awais Ahmed", Age=21 },            new Employee(){ ID=9, FullName="Aamir Hasan", Age=20 },          };        return emp;    }    public class Employee    {        public int ID { get; set; }        public String FullName { get; set; }        public int Age { get; set; }    } Note: You can get distinct values of any column by using above  linq query syntax. Output Download Linq-Distinct-column-fetch-records.zip (1.11 kb) See live demo
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